| CCNA Lab Console: | Interfaces - /28 Lab |
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A Newspaper conglomerate has decided to provide network connectivity for three branches within the organization. Each branch is to have one LAN. NewC router is completely configured. Given a network of 192.168.199.0/28 - add serial interface 0 and serial interface 1 to NewsA router and NewsB router respectively. Select the first available IP address for the serial 0 interface and the second available IP address for the serial 1 interface using the 2nd usable subnet (excluding subnet 0). The routers have been configured with the following specifications.
The routers are named NewsA, NewsB and NewsC. |
| Tips: Use Host B to connect to the NewsA router and Host D to connect to NewsB router. Toggle F11 to access/exit fullscreen mode. |
| Successful Lab Completion |
You will not be told this on the actual exam but you have successfully completed the first component of this Lab.
Good job! |
| Successful Lab Completion |
You will not be told this on the actual exam but you have successfully completed the second component of this Lab.
Good job! |
| ? - Lab Help |
We need to write down an outline of the question ... Class C Network: 192.168.199.0 /28 2nd usable subnet on /28 network - exclude subnet 0 NewsA Serial0 (DCE) - clock rate 1st available IP address NewsB Serial1 2nd available IP address Host B is serially connected to CeltA Host D is serially connected to CeltB PW: cisco
Now do the Subnet Calc: Magic Number Calc: 256 - 240 = 16 Create subnets: S Host Range Broacast .0 .16 .32 .33 - .46 .47 .482nd usable subnet is .32 1st and 2nd available IP addresses are .33 & .34 Write down input statements for CeltA: ip address 192.168.199.33 255.255.255.240Write down input statements for CeltB: ip address 192.168.199.34 255.255.255.240Now input your statements into the Command Line Interface on both CeltA and CeltB. |